先记录三个面试题

获取list中重复次数最多的一个数

def countFreNum(targetList):
    """
    获取list中重复次数最多的一个数
    方案:通过遍历list,将list元素添加到dict中的key,重复次数作为value,对value做排序找出重复次数最多的元素
    :param targetList: 入参
    :return:
    """
    #
    if not isinstance(targetList, list):
        return "目标内容非list"
    if len(targetList) == 0:
        return "目标list内容为空"
    # 保存统计结果到dict中
    res = {}
    for i in targetList:
        if i in res.keys():
            res[i] = res[i] + 1
        else:
            res[i] = 1
        print (res)

    # 将dict中value转为list 遍历list排序
    valueList = list(res.values())
    for li in range(len(valueList) - 1):
        for lj in range(li+1, len(valueList)):
            if valueList[li] <= valueList[lj]:
                valueList[li], valueList[lj] = valueList[lj], valueList[li]

    print(valueList)
    # 取最大的value值 遍历dict取key值 出现次数最多的数,可能不止一个
    freNum =[]
    for k, v in res.items():
        if v == valueList[0]:
            freNum.append(k)

    print("重复出现次数最多的数:" + ', '.join(str(i) for i in freNum) + ", 重复出现" + str(valueList[0]) + "次")
    return freNum

查找字符串中对应字符串，并替换

def replaceStr(rStr, reStr, repStr):
    """
    查找字符串中对应字符串，并替换
    方案: 循环做查找替换操作，用while， for循环会叠字查找多次问题(补充说明)("aaaaaaab", "aa")
    :param rStr: 原字符串
    :param reStr: 要查找替换的字符串
    :param repStr: 要替换为的字符串
    :return:
    """
    targetStr = ""
    reLen = len(reStr)
    count = 0
    
    while count < len(rStr):
        print( count)
        if rStr[count:count + reLen] == reStr:
            targetStr = targetStr + repStr
            count = count + reLen
        else:
            targetStr = targetStr + rStr[count]
            count = count + 1
    print(targetStr)
    return targetStr

获取输入整数的最小不重复数

def minNum(num):
    """
    获取输入参数的最小不重复数
    不重复数定义：每一位上的数与相邻的两个数都不相等
    方案: 遍历一个数字所有位上的数，如果出现任意一个两个相邻的数相等即不是要找的数
    :param num: 原数据
    :return: 不重复数
    """
    if not isinstance(num, int):
        return "目标内容非整数数值"
    if num < 10:
        return num
    tag = True
    while tag:
        num = num + 1
        numStr = str(num)
        count = 0
        for i in range(0, len(numStr)-1):
            if numStr[i] == numStr[i+1]:
                count = count + 1
        if count == 0:
            break
    print(num)
    return num