原生js实现字符串去除两边的空格
var Str = " qwert ",
function Remmovespace(str){
var str1 = Str.replace(/^\s*|\s$/g,"")
}
Remmovespace(Str);
结果: qwert
这个题目不是很明白:
var num = 1;
var obj = {
num: 2,
fn: (function() {
this.num *= 2;
num += 3;
var num = 1;
return function() {
num += 2;
this.num += 2;
console.log(++num, "xxx");
};
})()
};
var f = obj.fn;
f();
obj.fn();
console.log(window.num, obj.num);
原生js字符串去重:
var str = "aahhgggsssjjj";
var str1 = str.split("");
for (var i = 0; i < str1.length; i++) {
var arr = [];
if (arr.indexOf(str1[i] == -1)) {
arr.push(str1[i]);
}
console.log(arr.join(""));
}
统计字符串出现的次数:
var str = "aahhgggsssjjj";
var str1 = str.split("");
var arr = [];
var count = 0;
var sum = [];
for (var i = 0; i < str1.length; i++) {
if (arr.indexOf(str1[i]) == -1) {
arr.push(str1[i]);
}
}
for (var j = 0; j < arr.length; j++) {
console.log(arr[j]);
for (var i = 0; i < str1.length; i++) {
console.log(str1[i]);
if (arr[j] == str1[i]) {
count++;
}
}
sum.push(count);
count = 0;
}
console.log(arr);
for (var i = 0; i < arr.length; i++) {
var str3 = sum[i] % 2 == 0 ? "偶数" : "奇数";
console.log(arr[i] + "出现了" + sum[i] + "次");
console.log(arr[i] + "出现了" + str3 + "次");
}
