题目如下：
题目
这道题我的解法效率不是特别高，抛砖引玉，代码如下，我会找时间重新再写另外一个解法：
class Solution:
def reverseKGroup(self, head, k):
"""
:type head: ListNode
:type k: int
:rtype: ListNode
"""
if head is None or head.next is None or k == 1:
return head
temp = []
reverse_list = []
while head is not None:
temp.append(head.val)
head = head.next
if k == len(temp):
temp.reverse()
cur = ListNode(temp[0])
head = cur
cur = ListNode(temp[1])
head.next = cur
for j in range(2, len(temp)):
cur.next = ListNode(temp[j])
cur = cur.next
return head
i = 0
while i + k <= len(temp):
re_temp = temp[i:i + k]
re_temp.reverse()
for t in re_temp:
reverse_list.append(t)
i = i + k
for t in temp[i:]:
reverse_list.append(t)
cur = ListNode(reverse_list[0])
head = cur
cur = ListNode(reverse_list[1])
head.next = cur
for j in range(2, len(reverse_list)):
cur.next = ListNode(reverse_list[j])
cur = cur.next
return head
其它题目：leetcode题目答案讲解汇总（Python版 持续更新）
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