coding题目。思路是二分法。不多赘述。
from pwn import *
import pwnlib
import time
local = 0
if local:
p = process("./333")
else:
p = remote("pwnable.kr",9007)
for i in range(31):
print p.recvline()
while True:
n_c = p.recvline()
print n_c
# 所有验证通过，进入交互状态
if 'N=' not in n_c:
p.interactive()
n_c = n_c.split(' ')
n = int(n_c[0][2:])
c = int(n_c[1][2:])
print n,c
# 特别处理N=1,C=0的情况
if n == 1:
p.sendline('0')
print p.recvline()
continue
data = range(n)
for i in range(c)[::-1]:
if len(data) > 2**i:
data1 = data[0:2**i]
data2 = data[2**i:]
p.sendline(' '.join([str(j) for j in data1]))
#print ' '.join([str(j) for j in data1])
weight = int(p.recvline())
#print weight
if weight == (2**i)*10:
data = data2
else:
data = data1
if i == 0:
print data[0]
p.sendline(str(data[0]))
res = p.recvline()
print res
# 这里用于处理chance过多的情况
while 'Correct!' not in res:
p.sendline(str(data[0]))
res = p.recvline()
print res
