字符映射一下，后面只保存k这个序号即可
#include<iostream>
#include<cstring>
#include<algorithm>
#include<string>
using namespace std;
char s[3] = { 'W','T','L' };
int main()
{
double a[3];
double ans = 1;
for (int i = 0; i < 3; i++)
{
int k = 0;
for (int j = 0; j < 3; j++)
{
scanf("%lf", &a[j]);
if (a[j] > a[k])k = j;
}
printf("%c ", s[k]);
ans *= a[k];
}
printf("%.2f", (ans*0.65-1)*2);
return 0;
}
