python 脚本 实现 luajit 批量加密
# -*- coding: utf-8 -*-
import os
import subprocess
defaultSrcFolder = '../../XXX/src'
defaultTargetFolder = '../../XXX/src_jit_android'
filenums = 0
# luaJit encrypt src files to target folder
def encryptFile(src, out):
global filenums
for i in os.listdir(src):
path_file = os.path.join(src, i)
out_file = os.path.join(out, i)
if os.path.isfile(path_file):
if not os.path.exists(out):
os.makedirs(out)
if not os.path.exists(out_file):
cmdStr = 'luajit -b' + ' ' + path_file + ' ' + out_file
filenums += 1
print 'encrypting ', out_file
subprocess.call(cmdStr, shell=True)
if os.path.isdir(path_file):
encryptFile(path_file, out_file)
def del_file(path):
if not os.path.exists(path):
return
for i in os.listdir(path):
path_file = os.path.join(path, i)
if os.path.isfile(path_file):
os.remove(path_file)
else:
del_file(path_file)
os.rmdir(path_file)
if __name__ == '__main__':
# drag src folder into
folder = raw_input('drag src folder:')
if len(folder) == 0:
folder = defaultSrcFolder
outfolder = raw_input('input out folder(or use default): ')
if len(outfolder) == 0:
outfolder = defaultTargetFolder
del_file(outfolder)
encryptFile(folder, outfolder)
print 'encrypt successful, %s files in total ' % filenums
