题目：输入某年某月某日，判断这一天是这一年的第几天？
程序分析：以3月5日为例，应该先把前两个月的加起来，然后再加上5天即本年的第几天，特殊情况，闰年且输入月份大于2时需考虑多加一天
方法一：
# -*- coding:utf-8 -*-
year = int(raw_input('year:'))
month = int(raw_input('month:'))
day = int(raw_input('day:'))
months = (0,31,56,90,120,151,181,212,243,273,304,334)
if 0 < month <= 12:
sum = months[month - 1]
else:
print 'data error'
sum += day
leap = 0
if (year % 400 == 0) or ((year % 4 == 0) and (year % 100 == 0)):
leap = 1
if (leap == 1)and (month > 2):
sum += 1
print 'it is the %dth day in this year.' % sum
方法二:
# -*- coding:utf-8 -*-
import time
input_time = raw_input("请输入年份，格式如2017-08-30：")
num = time.strptime(input_time, '%Y-%m-%d').tm_yday
print "the {} day of this year!" .format(num)
