核心原因

Vector源码中大量使用synchronized 关键字，导致性能大幅度降低

    public synchronized void addElement(E obj) {
        modCount++;
        ensureCapacityHelper(elementCount + 1);
        elementData[elementCount++] = obj;
    }

    /**
     * Removes the first (lowest-indexed) occurrence of the argument
     * from this vector. If the object is found in this vector, each
     * component in the vector with an index greater or equal to the
     * object's index is shifted downward to have an index one smaller
     * than the value it had previously.
     *
     * <p>This method is identical in functionality to the
     * {@link #remove(Object)} method (which is part of the
     * {@link List} interface).
     *
     * @param   obj   the component to be removed
     * @return  {@code true} if the argument was a component of this
     *          vector; {@code false} otherwise.
     */
    public synchronized boolean removeElement(Object obj) {
        modCount++;
        int i = indexOf(obj);
        if (i >= 0) {
            removeElementAt(i);
            return true;
        }
        return false;
    }

    /**
     * Removes all components from this vector and sets its size to zero.
     *
     * <p>This method is identical in functionality to the {@link #clear}
     * method (which is part of the {@link List} interface).
     */
    public synchronized void removeAllElements() {
        modCount++;
        // Let gc do its work
        for (int i = 0; i < elementCount; i++)
            elementData[i] = null;

        elementCount = 0;
    }

推荐使用方法

使用Collections把一个list转为一个安全的，此方法是包装了一层，加了同步代码块，而不是像vector那样整个方法加同步

         ArrayList arrayList = new ArrayList();
        arrayList.add(1);
        arrayList.add(3);
        arrayList.add(4);
        Collections.synchronizedList(arrayList);

提高性能的原码

       public E get(int index) {
            synchronized (mutex) {return list.get(index);}
        }
        public E set(int index, E element) {
            synchronized (mutex) {return list.set(index, element);}
        }
        public void add(int index, E element) {
            synchronized (mutex) {list.add(index, element);}
        }
        public E remove(int index) {
            synchronized (mutex) {return list.remove(index);}
        }