L1-018. 大笨钟
问题描述:
java代码:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
int a = 0, b = 0;
Scanner input = new Scanner(System.in);
String s_time = input.next();
String s1[] = s_time.split(":");
int h = Integer.parseInt(s1[0]);
int m = Integer.parseInt(s1[1]);
if (m > 0) {
b = 1;
}
if (h - 12 == 0 && b != 0) {
System.out.print("Dang");
}
if (h - 12 < 0 || (h-12==0&&b==0) ){
System.out.print("Only " + s_time + ". Too early to Dang.");
} else {
a = h - 12;
}
if (h - 12 > 0) {
for (int i = 0; i < a + b; i++) {
System.out.print("Dang");
}
}
}
}
结果