Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
For example,
Given [100, 4, 200, 1, 3, 2],
The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4.
Your algorithm should run in O(n) complexity.
一刷
题解：
用map<Integer, Integer>来存储数字和对应的consecutive的长度。
比如{1,2,3,4,5}，就将长度信息5保存在1，5中。每次只更新boundary和数字n
public class Solution {
public int longestConsecutive(int[] num) {
int res = 0;
HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
for (int n : num) {
if (!map.containsKey(n)) {
int left = (map.containsKey(n - 1)) ? map.get(n - 1) : 0;
int right = (map.containsKey(n + 1)) ? map.get(n + 1) : 0;
// sum: length of the sequence n is in
int sum = left + right + 1;
map.put(n, sum);
//very important, in case, duplicate will 算出左边的sum和右边的sum, 其实算了重复的两次
// keep track of the max length
res = Math.max(res, sum);
// extend the length to the boundary(s)
// of the sequence
// will do nothing if n has no neighbors
map.put(n - left, sum);
map.put(n + right, sum);
}
}
return res;
}
}
