问题：
方法：
特殊情况特殊处理，其他情况对cur进行整除和取余数操作，直到cur为0。
package com.eric.leetcode
class IntegerToRoman {
fun intToRoman(num: Int): String {
var cur = num
val result = StringBuilder()
while (cur != 0) {
if (cur >= 1000) {
val M = cur / 1000
cur %= 1000
result.append("M".repeat(M))
} else if (cur >= 900) {
cur -= 900
result.append("CM")
} else if (cur >= 500) {
val D = cur / 500
cur %= 500
result.append("D".repeat(D))
} else if (cur >= 400) {
cur -= 400
result.append("CD")
} else if (cur >= 100) {
val C = cur / 100
cur %= 100
result.append("C".repeat(C))
} else if (cur >= 90) {
cur -= 90
result.append("XC")
} else if (cur >= 50) {
val L = cur / 50
cur %= 50
result.append("L".repeat(L))
} else if (cur >= 40) {
cur -= 40
result.append("XL")
} else if (cur >= 10) {
val X = cur / 10
cur %= 10
result.append("X".repeat(X))
} else if (cur == 9) {
cur -= 9
result.append("IX")
} else if (cur >= 5) {
val V = cur / 5
cur %= 5
result.append("V".repeat(V))
} else if (cur == 4) {
cur -= 4
result.append("IV")
} else {
val I = cur / 1
cur %= 1
result.append("I".repeat(I))
}
}
return result.toString()
}
}
fun main() {
val input = 9
val integerToRoman = IntegerToRoman()
print(integerToRoman.intToRoman(input))
}
有问题随时沟通
