文章作者：Tyan
博客：noahsnail.com | CSDN | 简书
1. Description
Student Attendance Record I
2. Solution
class Solution {
public:
bool checkRecord(string s) {
int absent = 0;
int late = 0;
for(int i = 0; i < s.length(); i++) {
char ch = s[i];
if(ch == 'A') {
absent++;
if(absent > 1) {
return false;
}
}
if(ch == 'L') {
if(i + 1 < s.length() && s[i + 1] == 'L') {
if(i + 2 < s.length() && s[i + 2] == 'L') {
return false;
}
}
}
}
return true;
}
};
