1.声明一个字典保存一个学生的信息，

学生信息中包括: 姓名、年龄、成绩(单科)、电话、性别(男、女、不明)

dic1 = {"name": "aa", "age": 18, "math": 85, "tel": "785613545466", "gender": "男"}
dic2 = {"name": "bb", "age": 17, "math": 80, "tel": "785613545467", "gender": "女"}
dic3 = {"name": "cc", "age": 19, "math": 98, "tel": "785613545468", "gender": "不明"}
dic4 = {"name": "dd", "age": 20, "math": 59, "tel": "685613545468", "gender": "男"}
dic5 = {"name": "ee", "age": 18, "math": 40, "tel": "785613545463", "gender": "女"}
dic6 = {"name": "ff", "age": 16, "math": 90, "tel": "785613545461", "gender": "不明"}

2.声明一个列表，在列表中保存6个学生的信息(6个题1中的字典)

stu_list = [
    {"name": "aa", "age": 18, "math": 85, "tel": "785613545466", "gender": "男"},
    {"name": "bb", "age": 17, "math": 80, "tel": "785613545467", "gender": "女"},
    {"name": "cc", "age": 19, "math": 98, "tel": "785613545468", "gender": "不明"},
    {"name": "dd", "age": 20, "math": 59, "tel": "685613545468", "gender": "男"},
    {"name": "ee", "age": 18, "math": 40, "tel": "785613545463", "gender": "女"},
    {"name": "ff", "age": 16, "math": 90, "tel": "785613545461", "gender": "不明"}
        ]

a.统计不及格学生的个数

count = 0
for student in stu_list:
    if student["math"] < 60:
        count += 1
        pass
    else:
        continue
        pass
    pass
print(count)

b.打印不及格学生的名字和对应的成绩

for student in stu_list:
    if student["math"] < 60:
        print(student["name"], student["math"])
        pass
    else:
        continue
        pass
    pass

c.统计未成年学生的个数

count = 0
for student in stu_list:
    if student["age"] < 18:
        count += 1
        pass
    else:
        continue
        pass
    pass
print(count)

d.打印手机尾号是8的学生的名字

for student in stu_list:
    if student["tel"][-1] == "8":
        print(student["name"])
        pass
    else:
        continue
        pass
    pass

e.打印最高分和对应的学生的名字

max_math = 0
name = ''
for student in stu_list:
    stu_math = student["math"]
    if stu_math > max_math:
        max_math = stu_math
        name = student['name']
        pass
    pass
print(name, max_math)

f.将列表按学生成绩从大到小排序(挣扎一下，不行就放弃)

for i in range(len(stu_list)):
    for j in range(len(stu_list)):
        if stu_list[i]["math"] > stu_list[j]["math"]:
            stu_list[i], stu_list[j] = stu_list[j], stu_list[i]
            pass
        pass
    pass
print(stu_list)

# 方法2
stu_list2 = stu_list
scores = []
# 取出所有成绩
for i in range(len(stu_list2)):
    scores.append(stu_list2[i]['math'])
    pass
print(scores)
scores.sort(reverse=True)
print(scores)
# 将所有对应成绩存入列表
new_stu_list = []
for score in scores:
    for student in stu_list2[:]:
        if score == student['math']:
            new_stu_list.append(student)
            stu_list2.remove(student)
            break
            pass
        pass
    pass
print(new_stu_list)

# 选择排序
for student in stu_list[:]:
    if student["gender"] == "不明":
        stu_list.remove(student)
        pass
    pass
print(stu_list)

3.用三个列表表示三门学科的选课学生姓名(一个学生可以同时选多门课)

list_math = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']
list_chinese = ['g', 'd', 'q', 'h', 'l', 'v']
list_english = ['g', 'b', 'h', 'm', 'e']

set_math = set(list_math)
set_chinese = set(list_chinese)
set_english = set(list_english)

a. 求选课学生总共有多少人

set1 = set_math | set_english | set_chinese
print(len(set1))

b. 求只选了第一个学科的人的数量和对应的名字

set1 = (set_math & (set_chinese ^ set_math ^ set_english)) - (set_math & set_english & set_chinese)
print(len(set1), '  ', set1)

c. 求只选了一门学科的学生的数量和对应的名字

set2 = (set_math ^ set_english ^ set_chinese ) - (set_math & set_english & set_chinese)
print(len(set2), set2)

d. 求只选了两门学科的学生的数量和对应的名字

set1 = set_math | set_english | set_chinese
# 只选了一门学科
set2 = (set_math ^ set_english ^ set_chinese ) - (set_math & set_english & set_chinese)
# 选了三门学科
set3 = set_math & set_english & set_chinese
set4 = set1 - set2 - set3
print(len(set4), set4)

e. 求选了三门学生的学生的数量和对应的名字

set3 = set_math & set_english & set_chinese
print(len(set3), set3)