Reverse digits of an integer.
Example1: x = 123, return 321
Example2: x = -123, return -321
Note:
The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.
将一个整数中的数字进行颠倒，当颠倒后的整数溢出时，返回 0 (标记为 32 位整数)。
分析
通过取余得到最后一位，循环，对于溢出进行判断即可
代码
public int reverse(int x) {
int result = 0;
while(x != 0) {
int tail = x % 10;
int newResult = result * 10 + tail;
if((newResult-tail)/10 != result)
return 0;
result = newResult;
x = x/10;
}
return result;
}
image.png
