Given a binary array, find the maximum number of consecutive 1s in this array.
给定一二进制序列，找出其中最大的连续为1的序列的元素数目。

Example 1:Input:[1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
The maximum number of consecutive 1s is 3.

Note:

• The input array will only contain 0 and 1.
• The length of input array is a positive integer and will not exceed 10,000

注：

• 输入序列只包含0和1
• 输入序列的长度为正整数且不会超过10000

思路：

class Solution(object):
    def findMaxConsecutiveOnes(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        res=0
        cur=0
        for i in nums:
            if i==1:
                cur+=1
            else:
                cur=0
            if cur>res:
                res=cur
        return res