亲测有效
#!/usr/bin/env python
#coding=utf-8
import os,sys
# 需要修改的类名前缀(需要替换)
pre_str = 'xxx'
# 新的类名前缀(需要替换)
pre_to_str = 'xxx_'
# 搜寻以下文件类型(自己需要替换)
suf_set = ('.h', '.m', '.xib', '.storyboard', '.mm', '.pch','.swift')
# 项目路径(需要替换)
project_path = '/Users/jyj/Desktop/Demo_ios'
# 项目配置文件路径(需要替换)(显示包内容 app.xcodeproj)
pbxpro_path = '/Users/jyj/Desktop/Demo_ios/AppName.xcodeproj/project.pbxproj'
# 文件重命名函数,返回新的文件名
def file_rename(file_path):
root_path = os.path.split(file_path)[0] # 文件目录
root_name = os.path.split(file_path)[1] # 文件名包含扩展名
filename = os.path.splitext(root_name)[0]; # 文件名
filetype = os.path.splitext(root_name)[1]; # 文件扩展名
new_path = os.path.join(root_path, filename.replace(pre_str, pre_to_str) + filetype) # 拼接新路径
os.renames(file_path, new_path) # 文件重命名
return filename.replace(pre_str, pre_to_str)
# 定义一个字典 key=旧类名 value=新类名
needModifyDic = {}
# 遍历文件,符合规则的进行重命名
for (root, dirs, files) in os.walk(project_path):
for file_name in files:
if file_name.startswith((pre_str,)) and file_name.endswith(suf_set):
old_name = os.path.splitext(file_name)[0]
new_name = file_rename(os.path.join(root, file_name))
needModifyDic[old_name] = new_name
# 遍历文件,在文件中更换新类名的引用
print(needModifyDic)
for (root, dirs, files) in os.walk(project_path):
for file_name in files:
if file_name.endswith(suf_set):
print('-----fileName-------' + file_name)
with open(os.path.join(root, file_name), 'r+') as f:
print('========fileName========' + file_name)
s0 = f.read()
f.close()
for key in needModifyDic:
if key in s0:
with open(os.path.join(root, file_name), 'r+') as f4:
s1 = f4.read().replace(key, needModifyDic[key])
print(key + ' ------> ' + needModifyDic[key])
f4.seek(0)
f4.write(s1)
f4.truncate()
f4.close()
# 替换配置文件中的类名
for key in needModifyDic:
with open(pbxpro_path, 'r+') as f:
s0 = f.read()
f.close()
if key in s0:
with open(pbxpro_path, 'r+') as f2:
s = f2.read().replace(key, needModifyDic[key])
f2.seek(0)
f2.write(s)
f2.truncate()
f2.close()