题目

两个参数，一个叫good，一个叫evil。
格式都为“整数（空格）整数（空格）整数……”的字符串，good含有6个整数，evil含有7个整数。
不同位置的整数有不同的价值。
good的是：[1, 2, 3, 3, 4, 10]； evil的是[1, 2, 2, 2, 3, 5, 10]
整数与它位置对应的价值的乘积表示这个位置的总价值
所有位置的总价值汇总表示最终的总价值
求出good和evil总价值，并对比。
Description

Middle Earth is about to go to war. The forces of good will have many battles with the forces of evil. Different races will certainly be involved. Each race has a certain 'worth' when battling against others. On the side of good we have the following races, with their associated worth:

Hobbits - 1
Men - 2
Elves - 3
Dwarves - 3
Eagles - 4
Wizards - 10
On the side of evil we have:

Orcs - 1
Men - 2
Wargs - 2
Goblins - 2
Uruk Hai - 3
Trolls - 5
Wizards - 10
Although weather, location, supplies and valor play a part in any battle, if you add up the worth of the side of good and compare it with the worth of the side of evil, the side with the larger worth will tend to win.

Thus, given the count of each of the races on the side of good, followed by the count of each of the races on the side of evil, determine which side wins.

Input:

The function will be given two parameters. Each parameter will be a string separated by a single space. Each string will contain the count of each race on the side of good and evil.

The first parameter will contain the count of each race on the side of good in the following order:

Hobbits, Men, Elves, Dwarves, Eagles, Wizards.
The second parameter will contain the count of each race on the side of evil in the following order:

Orcs, Men, Wargs, Goblins, Uruk Hai, Trolls, Wizards.
All values are non-negative integers. The resulting sum of the worth for each side will not exceed the limit of a 32-bit integer.

Output:

Return ""Battle Result: Good triumphs over Evil" if good wins, "Battle Result: Evil eradicates all trace of Good" if evil wins, or "Battle Result: No victor on this battle field" if it ends in a tie.

我的代码

function goodVsEvil(good, evil){
    let good_array = good.split(" ");
    let good_force = [1, 2, 3, 3, 4, 10];
    let g = 0;
    for (i=0; i<6; i++) {
         g += good_array[i] * good_force[i];
    }
    
    let evil_array = evil.split(" ");
    let evil_force = [1, 2, 2, 2, 3, 5, 10];
    let e = 0;
    for (i=0; i<7; i++) {
         e += evil_array[i] * evil_force[i];
    }
    
    let good_win = "Battle Result: Good triumphs over Evil";
    let evil_win = "Battle Result: Evil eradicates all trace of Good";
    let peace = "Battle Result: No victor on this battle field";
    let result;
    
    g != e ? result = (g > e ? result = good_win : result = evil_win) : result = peace;
    console.log(result);
    
    return result;
}

别人的代码

function goodVsEvil(good, evil) {  
  var getWorth = function( side, worth ) {
    return side.split(' ').reduce( function(result, value, index) { 
      return result + (worth[index] * value);
    }, 0);
  }

  var result = getWorth( good, [1,2,3,3,4,10] ) - getWorth( evil, [1,2,2,2,3,5,10] );

  return result > 0 ? "Battle Result: Good triumphs over Evil" :
         result < 0 ? "Battle Result: Evil eradicates all trace of Good" :
                      "Battle Result: No victor on this battle field";
}

我的感想

题目翻译起来太绕了额……