实现问题
1.如何判断切换路由时是前进还是后退
2.每次切换时向左向右切换动画如何实现
实现原理
1.我们需要给各个页面定义层级,在切换路由时判断用户是进入哪一层页面,如果用户进入更高层级那么做前进动画,如果用户退到低层级那么做后退动画.
import Vue from 'vue'
import VueRouter from 'vue-router'
import Home from '../views/home/Home.vue'
Vue.use(VueRouter)
let routes = [
{
path: '/',
redirect: '/home'
},
{
path: '/home',
name: 'home',
component: Home,
meta: {
showMenu: true,
index:0 //meta对象的index用来定义当前路由的层级,由小到大,由低到高
},
},
{
path: '/login',
name: 'login',
component: () => import("@/views/login/login"),
meta: {
showMenu: false,
},
},
{
path: '/register',
name: 'register',
component: () => import("@/views/login/register"),
meta: {
showMenu: false,
},
},
{
path: '/retrievePassword',
name: 'retrievePassword',
component: () => import("../views/mine/retrievePassword.vue")
meta: {
showMenu: false,
},
}
]
2.监控路由跳转,判断切换页面之间的层级关系,并以此来判断路由前进或者后退App.vue.
<template>
<div id="app">
<footer-menu v-if="showMenu" />
<transition :mode="mode" :name="transitionName">
<router-view class="center"></router-view>
</transition>
</div>
</template>
<script>
export default{
data() {
return {
mode: '',
transitionName: 'slide-left', //默认动画
};
},
watch: {
$route(to, from) {
//页面切换动画
console.log(to);
let toName = to.name;
const toIndex = to.meta.index;
const fromIndex = from.meta.index;
if (toIndex == undefined) {
this.mode = 'out-in';
this.transitionName = '';
} else {
this.mode = '';
this.transitionName = toIndex < fromIndex ? 'slide-right' : 'slide-left';
}
},
},
}
</script>
3.编写slide-left 和 slide-right 类的动画
// -----------
/*app.vue 的style*/
.slide-right-enter-active,
.slide-right-leave-active,
.slide-left-enter-active,
.slide-left-leave-active {
will-change: transform;
transition: all 500ms;
position: absolute;
}
.slide-right-enter {
opacity: 0;
transform: translate3d(-100%, 0, 0);
}
.slide-right-leave-active {
opacity: 0;
transform: translate3d(100%, 0, 0);
}
.slide-left-enter {
opacity: 0;
transform: translate3d(100%, 0, 0);
}
.slide-left-leave-active {
opacity: 0;
transform: translate3d(-100%, 0, 0);
}